What will be the difference between simple interest and compound interest at 4% per annum on a sum of ₹5000 after 3 years

What will be the difference between simple interest and compound interest at 4% per annum on a sum of ₹5000 after 3 years, math , EDUTICAL, edutical.c
Pijus Kumar Sir

Question: What will be the difference between simple interest and compound interest at 4% per annum on a sum of ₹5000 after 3 years ?

  • 24.32
  • 36.32
  • 25 
  • 30.24 

Answer: 

To find the difference between simple interest (SI) and compound interest (CI) at a rate of 4% per annum on a sum of ₹5000 after 3 years, we use the following formulas:

1. Simple Interest 

SI=P×R×T100SI = \frac{P \times R \times T}{100}


P=5000P = 5000,
R=4%R = 4\%,
T=3T = 3 years.

SI=5000×4×3100=600100=600SI = \frac{5000 \times 4 \times 3}{100} = \frac{600}{100} = 600

2. Compound Interest :

CI=P(1+R100)TP CI=5000(1+4100)35000CI = 5000 \left(1 + \frac{4}{100} \right)^3 - 5000 CI=5000(1.04)35000CI = 5000 \left(1.04\right)^3 - 5000 CI=5000×1.1248645000CI = 5000 \times 1.124864 - 5000 CI=5624.325000CI = 5624.32 - 5000 CI=624.32

Difference=CISI=624.32600=24.32

Additional Method :

 Difference=P×R21002×T(T1)/2\text{Difference} = \frac{P \times R^2}{100^2} \times T (T - 1) / 2

For 3 years, a simple shortcut formula is:

Difference=P×R21002×3\text{Difference} = \frac{P \times R^2}{100^2} \times 3

  • Principal (P) = ₹5000
  • Rate of Interest (R) = 4% per annum
  • Time (T) = 3 years


 Difference=5000×421002×3\text{Difference} = \frac{5000 \times 4^2}{100^2} \times 3 =5000×1610000×3= \frac{5000 \times 16}{10000} \times 3 =8000010000×3= \frac{80000}{10000} \times 3 =8×3= 8 \times 3 =24= 24

** The difference between CI and SI after 3 years is ₹24

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