In an exam one student get 25% marks and fails by 30 marks. Another student get 40% which is 60 more than the passing mark. Find full marks in the exam?

In an exam one student get 25% marks and fails by 30 marks. Another student get 40% which is 60 more than the passing mark Find full marks in the exam
Pijus Kumar Sir

Questions : In an exam one student get 25% marks and fails by 30 marks. Another student get 40% which is 60 more than the passing mark. Find full marks in the exam ?

  •  150
  •  600
  •  180 
  •  None 

Answer:  

 Let the full marks of the exam be x and the passing marks be p.

Given conditions:

  1. A student who scores 25% of full marks fails by 30 marks

    0.25x=p300.25x = p - 30
  2. A student who scores 40% of full marks gets 60 marks more than the passing marks

    0.40x=p+600.40x = p + 60

Solving for x:

We have two equations:

  1. 0.25x=p300.25x = p - 30
  2. 0.40x=p+600.40x = p + 60

Subtract equation (1) from equation (2):

(0.40x0.25x)=(p+60)(p30)(0.40x - 0.25x) = (p + 60) - (p - 30) 0.15x=900.15x = 90 x=900.15=600x = \frac{90}{0.15} = 600

Answer:

The full marks in the exam are 600.

Additional Technique 

Here's how to solve this problem:

Let:

  • 'x' be the full marks of the exam.
  • 'p' be the passing marks.

Set up equations based on the given information:

  • Student 1: 0.25x = p - 30 (25% of the full marks is 30 marks less than the passing mark)
  • Student 2: 0.40x = p + 60 (40% of the full marks is 60 marks more than the passing mark)

Solve the equations:

One way to solve this is using substitution or elimination. Here's the substitution method:

  1. Solve for 'p' in the first equation:

    p = 0.25x + 30

  2. Substitute this value of 'p' into the second equation:

    0.40x = (0.25x + 30) + 60

  3. Simplify and solve for 'x':

    0.40x = 0.25x + 90

    0.15x = 90

    x = 90 / 0.15

    x = 600

Answer:

The full marks in the exam are 600.

CBSE / NCERT / SAT/ UPSC 
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