A can complete a work in 40 days. B is 25% more efficient than A. In how many days B alone can complete the work

Questions : A can complete a work in 40 days. B is 25% more efficient than A. In how many days B alone can complete the work ?

Answer:  

 We can solve this quickly using a direct shortcut approach:

1. A completes the work in 40 days.

   • So, A's work efficiency = 1/40 (fraction of work done per day).

2. B is 25% more efficient than A.

   • That means B does 1.25 times the work A does in a day.
   • So, B’s efficiency = 1.25 × (1/40) = 1/32 (work done per day).

3. Total work is 1 unit, so the number of days B needs:

   $$\text{Days} = \frac{1}{\text{B's efficiency}} = \frac{1}{1/32} = 32 \text{ days}$$

Final Answer:

B alone can complete the work in 32 days.

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